there are lots of ways. Pick"s organize tells us if the vertices are lattice clues the area a is

a = b/2 + i - 1

where b is the variety of boundary lattice points and also i is the variety of interior lattice points.

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in the number i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let"s shot the shoelace formula. The area is fifty percent the amount of the cross assets of the sides.

a(-2,6) -2(2)-6(-5) = 26

b(-5,2) -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3) 4(3) - (-3)(5) = 27

e(5,3) 5(3) - 3(1) = 12

f(1,3) 1(6) - 3(-2) = 12

a(-2,6)

each the the cross products is twice the area that the triangle through the associated side and also one crest the origin. Therefore the area that abo=26/2=13.

area = (1/2) (26 + 19 + 18 + 27 + 12 + 12) = 57

that checks!

Answer from: Quest

on your file it doesn"t say the answer yet the the answer is altitude

step-by-step explanation:

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