The stockroom insurance claims the percent acetic acid in vinegar to be $2.0\%$. The density of vinegar is $pu1.106 g mL-1$. Using mean molarity offered ($pu0.2844M$) calculate the mass percent acetic mountain in vinegar because that comparison to the stockroom claim.

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Not sure how to method the problem yet this is what I"ve done:

$$fracpu0.2844 molpu1L imes (pu60.05g mol-1) imes left(fracpu1Lpu1000mL ight) = pu 0.01707822 g mL-1$$

if you have $pu1000mL$, you"ll have $pu0.001106 g ext Acetic Acid div pu0.0000170782 g ext Vinegar$ so the will provide $\%$ the acetic acid? I could use part clarification in solving this

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$1000$ mL the vinegar will weigh $1106$ g and contain $1000 · 0.017078$ g the acetic acid (= $17.078$ g). Climate $17.078/1106 = 0.0154 = 1.54$% acetic acid.

The stockroom manager should be diluting the vinegar, probably for a details experiment. The vinegar i buy is $5$% acetic acid (rarely $4$%).

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answer Oct 16 "18 at 13:57

James GaidisJames Gaidis
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