Since there can be <-ℓ, ℓ> orientations and also since the orbital form f has ℓ = 3, we should have actually 7 possible orientations with 2 spins, for this reason $7 imes 2 = 14$, for this reason I thought the correct answer was D (14).

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However, I acquired it wrong and also the exactly answer is significant as C (2). Is that an error in the test, or to be I absent something?

You"re correct that there are seven feasible spatial orientations because that an f-type orbital, and also hence seven possible orbitals in one f-type sub-shell. However, the concern specifically asks because that the maximum number of electrons in one together orbital, and any single atomic orbital, nevertheless of the sub-shell type specified by $l$, deserve to only host two electrons. This is through virtue that the Pauli exemption principle. Fourteen would certainly be the maximum variety of electrons throughout an entire f-type sub-shell, however the question only asks around one orbital.

The inquiry specifically ask that no.of electron an orbit of f subshell have the right to hold.... As we know that f subshell save on computer 7 orbital and also each orbital have the right to hold best 2 electons so exactly answer would be 2..we have the right to simply recognize this by taking the real life instance imagine that there is home named f which consists of 7 rooms so similarly in this situation house is a subshell and each room is an orbital... Thank you,

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