I"m trying to do homework for my physics class, and also it claims I should find "the component of \$veca\$ along the direction of \$vecb\$". The vectors are:

\$veca = 7.1hat ns + 8.97 hat j \$

\$vecb = 5.8hat ns + 2.5hat j\$

I know exactly how to discover the \$x\$ and also \$y\$ components yet I"ve never done this before. How do I perform it?    Using the formula

\$\$ extcomp_b a = fraca cdot bvert b vert\$\$

with the offered vectors

\$\$veca = \$\$ \$\$vecb = \$\$ we get that

\$\$acdot b = cdot = (7.1cdot 5.8) + (8.9cdot 2.5) = 63.43\$\$

Then \$\$vert bvert = sqrt5.8^2 + 2.5^2 = sqrt33.64 + 6.25= sqrt39.89\$\$

Therefore the price is \$\$frac63.43sqrt39.89\$\$ I think the ingredient of A along B should be a vector. The ahead answer offers the size of the ingredient of A along B. Currently that need to be multiplied by a unit vector in the direction that B. So my answer would certainly be:

\$comp_bA = frac A cdot B\$ multiply by the vector \$frac B\$ we get \$frac A cdot B B = frac A cdot BB cdot B B\$

Then to acquire the component of A perpendicular come B, friend subtract that from A.

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Hint: the ingredient of \$a\$ follow me \$b\$ (also recognized as the scalar forecast of \$a\$ ~ above \$b\$) is provided by

\$\$ extcomp_b a = fraca cdot bvert b vert\$\$

where \$a cdot b\$ is the dot product.

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